Can u help me size this steam radiator

Joseph_4

I have a customer with old cabinet radiators with steel convectors being used for steam. cant find it in Dan's Edr book. The steel element is 6 inches in depth, 8 inches high and 29 inches wide. The cabinet its contained in is 22 inches high x 32 inches wide
thanks
Joe

Jamie Hall

pictures?

Steamhead

Post a pic including with the cover off. There were many different variations of the basic convector. Also, did you see any name or trademark on it?

Joseph_4

Joseph_4

couldnt find name
Joe

Joseph_4

any ideas?

Jamie Hall

No specific ideas -- but you can get a decent estimate of the EDR of that thing by taking the surface area of a fin -- count both sides -- and multiplying by the number of fins. Convert to square feet from square inches. Now -- that will be somewhat high, but not wildly so, but is only valid if the convector cover is on and the openings into that cover are not obstructed in any way.

Joseph_4

can u explain using the surface area of one fin that 6 x 8 inches and say there are 300 fins thx. dont i still need to know radiation of each fin?
Joe

bburd

6”x8”=48 sq.in. x 2 sides=96 sq. in. per fin.

96 sq. in. / 144 sq. in. per sq. ft. = 0.666 sq. ft. per fin

0.666 sq. ft. x 300 fins = 200 sq. ft.

Jamie Hall

Or you could alter the sequence of calculation -- the EDR of each fin is 0.666. Then just add them up...

Steamhead

@Joseph_4 , that might be a "Murray Radiator":

https://heatinghelp.com/heating-museum/murray-radiators/