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Boiler firing rate
kcopp
Member Posts: 3,827
in Oil Heating
Looking to replace a Peerless EC05 steam boiler.
I measured out the radiation as best I could (some really different CI convectors) and got a EDR number....it seemed low. I want to see what they were using for a firing rate.... boiler has a .50 gph 70W nozzle. Seemed way undersized for the boiler. I asked about the pressure firing rate and it was 1200 psi. Apparently this was an experimental burner. Anyone have an idea what the firing rate on a 1200psi half gallon/ hr is?
They are going to convert to gas so am I'm looking to eliminate the burner.
I measured out the radiation as best I could (some really different CI convectors) and got a EDR number....it seemed low. I want to see what they were using for a firing rate.... boiler has a .50 gph 70W nozzle. Seemed way undersized for the boiler. I asked about the pressure firing rate and it was 1200 psi. Apparently this was an experimental burner. Anyone have an idea what the firing rate on a 1200psi half gallon/ hr is?
They are going to convert to gas so am I'm looking to eliminate the burner.
0
Comments

Pump pressure is not 1200 psi. 120 psi maybe.0

Depending on the burner, that boiler should be fired on or over 1.5 gph @ 140 psi.
There's almost no reason to underfire a properly sized steam boiler.
But if you have a burner that fires at 1200 psi, I'd like to see it, and I'll come get it off of you.
Are they converting the boiler to gas, or replacing the boiler with gas?steve0 
1200 psi... not a typo.
It was an experimental burner a few years back. Preheat.
Happy to get pix.
Im sure he would be willing to sell it.
He actually invested money to get this onto the open market but it went bust.
The boiler is shot, back wall toast.
They are going to nat gas. Want a Nat gas unit now.
Big place.0 
I don't know how to do the math, but...
.50 nozzle @ 200 PSI is .71 GPH for a 42% increase.
.50 nozzle @ 300 PSI is .87 GPH for a 74% increase.
Is it safe to say that a .50 nozzle @ 1200 PSI is a tad over fired for the boiler?
I would like to see this burner. Maybe it needs a really long chamber.0 
Is that a "Burner Booster"?0

I believe so. It was a heck of a set up. Burned super clean he said.
0 
I went to see this when it was first advertised. The principle appeared sound, and probably would have gained traction 30 or so years ago. But at that time, gas was a lot less expensive and still is.1

here's the formula:
F1= nozzle flow rate at (100psi)
F2=nozzle flow rate at (1200psi)
P1=100 psi nozzle pressure
P2= 1200 psi new nozzle pressure
F2=F1 x (P2/P1) .5 (exponent)
No math wiz here I use a calculator or count on my fingers LOL
I'll bet a smat guy like @Jamie Hall could whip this out
0 
I have 2 engineering degrees and i'm not sure where .5(exponent) is supposed to go
Is it:
F2=F1 * ((P2/P1)^.5)
note that X^.5=squareroot(X)0 
@mattmia2
.5
Yes I think so Exponent applies to the P2
P1
They had it written like above with brackets around the P1 & P2
I guess some things you can't do on a keyboard
0 
Did you pay off both of those degrees or is there some kind of refund available...mattmia2 said:I have 2 engineering degrees and i'm not sure where .5(exponent) is supposed to go
Is it:
F2=F1 * ((P2/P1)^.5)
note that X^.5=squareroot(X)
Of course I'm teasing you...easy...easy everyone...lolsteve0 
I found what I was looking for on a Beckett nozzle chart.
Divide new oil pressure (1200) new pressure) by (100 std nozzle pressure=12
Find the square root of 12 (you can google it)=3.46410162
Multiply the square root you found (3.46410162) x nozzle rating @100psi in this case .50gph
3.46410162 x .50 (nozzle size) + a firing rate of 1.73205081 or 1.73 gph
The one I always have stuck in my head for some reason is a 12 gph nozzle @300psi will give you about 20gph
Answer: from Beckett Chart:20.79gph
Answer from calculation: 300/100=3, square root of 3 is 1.74something 1.74 x 12=20.880 

so it is this:
F2=F1 * ((P2/P1)^.5)
which is this:
F2=F1 * sqrt(P2/P1)0 
According to the little app I made, I agree with @EBEBRATTEd. However when I looked up that formula that @EdTheHeaterMan posted, one of the notes was that it's not as accurate at pressures over 300 psi.
steve0 
Wow! Thanks!
0 

Parentheses, exponents, multiplication & division, addition & subtraction.
P1=100
P2=1200
P2/P1=12
12^.5= 3.46410161514 or the square root of 12
F2=F1 * 3.46410161514
F2= .5 * 3.46410161514
F2= 1.73205080757steve0 
You don’t need the extra parentheses.mattmia2 said:so it is this:
F2=F1 * ((P2/P1)^.5)
which is this:
F2=F1 * sqrt(P2/P1)
F2=F1 * (P2/P1)^.5
Either way ya need a calculator…
steve0 
don't need them but it make it more clear when you aren't typesetting it the way you would write it0

I like the Beckett formula, much simpler for me at least0
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