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Member Posts: 103
edited January 2020
I believe the is a Weil-McLain but not sure. They also appear to have vents within the cast cabinet.

Any thoughts on which radiators these are would be fantastic. Thank you

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Weil-McLain Raydiant or Solray.
All Steamed Up, Inc.
Towson, MD, USA
Steam, Vapor & Hot-Water Heating Specialists
Oil & Gas Burner Service
Consulting
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You can calculate the square feet of steam for any radiator qan be pretty close to the ratings in Dans book.

Remember the old days way back when no one could figure out how to rate a radiator.

The people that manufactured boilers dipped the radiator into a tub of paint.

They then let the excess paint drip of the radiator back into the tub.

They then measured the amount of paint that was missing from the tub.

Lets say there was a glass of paint missing from the tub, they then took a glass of paint and painted a cast iron large billet. The paint would only cover so many square feet of metal.

They now knew how much paint was used to paint the radiator.
That radiator was now assigned a square foot of steam designation.

Some years ago before Dan published his book that rated the edr or hundreds of radiators I had a job to replace a boiler in home with 50 radiators. The boiler that was being removed was a coal fired boiler with no data plates or manufacturers name.

What I did was to measure each radiator, count the tubes and then imagined the tubes to be Flat, (no spaces between tubes)
And came up with the square feet of steam for each radiator.

Not entirely scientific, but the worst case is I would be over sizing by a small factor.

Sounds complicated but really easy just time consuming,

Jake
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Let’s say this rad is 25” x 30” with 25 sections. What would your math look like? Thank you for your insight
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If I run into an oddball radiator I use a cloth tape measure to find the circumference of a tube or column and then multiply it out to find the area of that one tube / column; then count the total number of them and your all set. That will get you within 5-10% and that's accurate enough.

Bob
Smith G8-3 with EZ Gas @ 90,000 BTU, Single pipe steam
Vaporstat with a 12oz cut-out and 4oz cut-in
3PSI gauge
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keith123 said:

Let’s say this rad is 25” x 30” with 25 sections. What would your math look like? Thank you for your insight

How many columns?

My math would look like this:
1. open up Dan's EDR book,
2. find the radiator or one that looks the most similar,
3. look up the EDR of that radiator with the same heght, number of columns and number of sections.
Just another DIYer | King of Prussia, PA
1983(?) Peerless G-561-W-S | 3" drop header, CG400-1090, VXT-24
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And if you didn't have the book on your shelf - would you wait for the mailman to deliver it?

Bob
Smith G8-3 with EZ Gas @ 90,000 BTU, Single pipe steam
Vaporstat with a 12oz cut-out and 4oz cut-in
3PSI gauge
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No, I'd probably ask one of the wallies to look it up for me, unless I had a PDF of the right catalog in my collection.
Just another DIYer | King of Prussia, PA
1983(?) Peerless G-561-W-S | 3" drop header, CG400-1090, VXT-24
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To Kieth123

Here is my math

Section measures 25x30 = 750 sq inches
each section has 2 sides
750sx2 = 1500 sq inches

1500 sq inches x 25 + 37,500 inches

1728 sq inches = 1 square foot

37,500 sq inches divided by 1728 square inches = 21.7 square feet of steam

The error factor is minimal

What I have done here is exploded the sections to the point where we have a flat plate section. what is not included is the 4 edges on each section.

Because of that I added 1 square foot of steam for the 100 edges not calculated.

This works when no data is for the radiator is available.

SO the radiator is 22.7 square feet of steam

Jake
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If anybody could come up with a formula for this it would be you!

I'll have to try it out on some of my radiators to see how close it comes to the ratings.
Just another DIYer | King of Prussia, PA
1983(?) Peerless G-561-W-S | 3" drop header, CG400-1090, VXT-24
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Nice try, but no cigar. Your math is off by a factor of 12.

A square ft is 12 inches by 12 inches, which = 144 square inches.

Unfortunately you calculated 144 x 12 = 1728, which is the number of cubic inches in a cubic foot.

I don't know the construction of your radiator, so I can't comment on the statement that each side is basically a flat plate.
I do not understand how you figured out there are 25 sections, there are 22 spaces between the verticals in the photo.

Here's a simpler way to look at it, if I understand the situation.

25" = 2 ft
30" = 2.5 ft
25 sections with 2 sides = 50 sides

2 x 2.5 x 50 = 5 x 50 = 250 sq ft.

That seems like a lot of sq ft for a single radiator. What are the overall length, width and height of the radiator?

Unless I am totally messed up, the sections are connected just like a free standing radiator, side by side as you look at them (like a loaf of bread). The sections themselves are only a few inches from front to back, so you don't have 25 sections that are 25 x 30. I have to assume the 25 x 30 are the visible front face of the radiator, but you don't mention how deep the radiator is. In looking for some decent information on that radiator, I found they can be anywhere from 2-1/2" to 7" deep. Dan's, "The Lost Art of Steam Heating, Revised" book says a cast iron radiant/convector 20" tall 5" deep radiator section has 2.25sq ft per section, 7" deep is 3.4.

There is a web site archives.org that I found and it has several catalogs of boiler and radiator manufacturers. The sketches of some of the equipment is pretty amazing (also, scary).

Somebody, please check what I am saying, since I am not familiar with these radiators.
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i USED SQUARE FOOT WHERE IT SHOULD HAVE BEEN CUBIC FOOT.

I EXPLODED THE RADIATOR INTO A THREE DIMENSIONAL BOX. \\

LETS TRY THE EXAMPLE OVER AGAIN