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Monoflow w/ 2 parallel elements connected?

wcs5050wcs5050 Member Posts: 126
Am I correct in saying that unless there is a valve/restriction on emitter #1, no flow will occur through emitter #2 under normal open pipe conditions due to pressure drop at #1.
8783FAD9-BDEA-4FE8-8D32-3E44326584CF.png
750 x 1334 - 376K

Comments

  • Jamie HallJamie Hall Member Posts: 10,383
    Not quite. If it is piped more or less as drawn, there will be much less flow through no. 2 than no. 1 -- but there will be some. The flow will split so that the head loss due to flow will be equal in the two paths.
    Jamie



    Building superintendent/caretaker, 7200 sq. ft. historic house museum with dependencies in New England.



    Hoffman Equipped System (all original except boiler), Weil-Mclain 580, 2.75 gph Carlin, Vapourstat 0.5 -- 6.0 ounces per square inch
  • wcs5050wcs5050 Member Posts: 126
    If distance between the two emitters is not equal, do we assume fractional flow in proportion to distance, or still split equally.
    30F57517-B837-4CE2-AA40-7D17591C6769.png
    750 x 1334 - 388K
  • Steve MinnichSteve Minnich Member Posts: 2,359
    I’d say more equally. The difference would be marginal.
    Steve Minnich
    Tell me I can't, and I'll show you I can.
  • Jamie HallJamie Hall Member Posts: 10,383
    wcs5050 said:

    If distance between the two emitters is not equal, do we assume fractional flow in proportion to distance, or still split equally.

    It depends on head loss, not distance directly. Head loss is a non-linear function of flow velocity, and thus of pipe sizes and type, as well as all the fittings -- including the size of the emitters. To take a ridiculous example, suppose those connecting pipes were 4 inch copper, and the emitters were half inch -- the flows would be within a whisker of being equal. Then suppose the other way around -- emitter number 2 would get much less.

    You can't eyeball it. You have to figure it out.
    Jamie



    Building superintendent/caretaker, 7200 sq. ft. historic house museum with dependencies in New England.



    Hoffman Equipped System (all original except boiler), Weil-Mclain 580, 2.75 gph Carlin, Vapourstat 0.5 -- 6.0 ounces per square inch
  • JUGHNEJUGHNE Member Posts: 5,648
    Are both tees of the diverter design?
  • Solid_Fuel_ManSolid_Fuel_Man Member Posts: 1,492
    If you only have one diverter tee setup and you want two emitters, the best way is reverse return the two emitters.

    But with those short distances it may not be necessary. I'd do it reverse return, then you are guaranteed equal flow.
    20190601_171141.jpg
    3024 x 4032 - 4M
    Master electrician specialising in boiler and burner controls, multiple fuel systems, radiant system controls, building controls, and universal refrigeration tech.
  • wcs5050wcs5050 Member Posts: 126
    Each tee on main run is monoflow/diversion type, correctly oriented upstream and downstream as required.
  • JUGHNEJUGHNE Member Posts: 5,648
    If there is lack of flow for these, perhaps the simplest thing would be to install a metering valve between the tees.
    Adjust the flow as needed.
  • Keith MKeith M Member Posts: 63
    Just pipe them in reverse return. Simple and quick and...it works.
    Keith Muhlmeister
    Slant/Fin Corporation
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