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Help needed w/heat loss calculation...

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john p_2
john p_2 Member Posts: 367
Trying to help a friend out and myself to understand heat loss a little better, maybe someone can shed some light on this for me.

Did a calculation on the US Boiler Company website and all results posted below but I don't understand...what/why is a range of temperatures given?

And by the way this calculation was being done for a possible garage unit heater in a 30' X 30' & 8' ceilings w/6" insulation

Total Heat Loss for 60 F Temp. Diff. = 31,209.00
Total Heat Loss for 70 F Temp. Diff. = 36,826.62
Total Heat Loss for 80 F Temp. Diff. = 41,820.06
Total Heat Loss for 90 F Temp. Diff. = 46,813.50
Total Heat Loss for 100 F Temp. Diff. = 51,806.94

Comments

  • BobC
    BobC Member Posts: 5,478
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    Different areas of the country have differed design temperatures (minimum expected).

    The temperature difference is between desired room temperature ( 70 degrees for a house) and the expected minimum temperature for your area (in my area it's 5 degrees).

    Bob
    Smith G8-3 with EZ Gas @ 90,000 BTU, Single pipe steam
    Vaporstat with a 12oz cut-out and 4oz cut-in
    3PSI gauge
  • john p_2
    john p_2 Member Posts: 367
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    Thanks so much Bob
  • BobC
    BobC Member Posts: 5,478
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    Your welcome. Don't ever be afraid to ask a question - someone on the forum will have an answer.

    Bob
    Smith G8-3 with EZ Gas @ 90,000 BTU, Single pipe steam
    Vaporstat with a 12oz cut-out and 4oz cut-in
    3PSI gauge
  • Ironman
    Ironman Member Posts: 7,376
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    36,826 btus = almost 41 btus per sq. ft. That sounds awful high.

    I would recommend that you down load SlantFin's heat loss app and use that. It will be a lot more accurate.

    Online calculators will grossly over-size.
    Bob Boan
    You can choose to do what you want, but you cannot choose the consequences.
  • john p_2
    john p_2 Member Posts: 367
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    I actually have the SlantFin & Taco's but found the US Boiler one and thought it might be a little easier for my friend to use and see for himself what kind of things go into a heat loss calculation.
    It is a garage on grade with uninsulated walls and two large garage doors.
  • Georgi
    Georgi Member Posts: 1
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    Formula: Heat Loss Through a Building Component = U-Factor x delta T x Area

    U factor is reverse on R factor. R Factor is cumulative of the thermal resistance of every component of the wall - sheeting, insulation, sheetrock or other interior finish. Add the R values for all of them. Then reverse as a fraction. For example if total R value is 18, then U value is 1/18. If R=25, then U=1/25.

    Delta T is the difference between the temperature outside and the temperature you want to maintain inside. Usually 65 F is used as a standard for indoor temperature. So if it is 20F out, delta T = 65-20=45. This is why the calculator you used gave you multiple options.

    Area - calculate all external walls and possibly ceiling. If the garage is detached (all walls and ceiling are external), then your area is 4 walls 30x8 + ceiling 30x30. If the garage is attached to a house, only 3 walls and a ceiling will be external. If the garage is part of the house, then only one wall is external.

    The number you get is your heat loss measured in BTU/hour. This is conductive heat loss through materials. Convective heat loss (through holes and gaps) is separate formula.

    Kind of late response, but I just recently found this forum. Maybe it will help somebody in the future.
    Ironman
  • Rich_49
    Rich_49 Member Posts: 2,766
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    Maybe there is someone in your area that knows how to do such things .
    You didn't get what you didn't pay for and it will never be what you thought it would .
    Langans Plumbing & Heating LLC
    732-751-1560
    Serving most of New Jersey, Eastern Pa .
    Consultation, Design & Installation anywhere
    Rich McGrath 732-581-3833