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BTU output with lower supply temps

Is there a method to determining the output of a radiator when supply temp is say 150 degrees versus a manuf listed output for a temp of 180?

I'm trying to oversize radiators so I can run lower temps and still meet design demand.

Comments

  • Tom Giedraitis
    Tom Giedraitis Member Posts: 44


    Is there a method to determining the output of a radiator when supply temp is say 150 degrees versus a manuf listed output for a temp of 180?

    I'm trying to oversize radiators so I can run lower temps and still meet design demand.

  • Dave_22
    Dave_22 Member Posts: 232


    There probably is a formula, but I have seen different supply/BTU Ft. charts on most of the manufacturers websites or literature. :)
  • Doug_7
    Doug_7 Member Posts: 249
    Heat output formula

    Heat output in Btu / hour is a function of the surface area of the radiator times the difference in temperature between the room and the radiator.

    For the 180 degree case the temperature difference is: 180 - 70 = 110

    For the 150 degree case the temperature difference is: 150 - 70 = 80

    80 / 110 = 73% as much heat output at 150 degrees compared to 180 degrees.

    If you increase radiator surface area by 27% you are back to the same heat output you started with because the temperature reduction and area increase offset each other.
  • JimGPE_3
    JimGPE_3 Member Posts: 240
    Watch the math...

    > Heat output in Btu / hour is a function of the

    > surface area of the radiator times the difference

    > in temperature between the room and the radiator.

    > For the 180 degree case the temperature

    > difference is: 180 - 70 = 110

    >

    > For the 150

    > degree case the temperature difference is: 150 -

    > 70 = 80

    >

    > 80 / 110 = 73% as much heat output at

    > 150 degrees compared to 180 degrees.

    >

    > If you

    > increase radiator surface area by 27% you are

    > back to the same heat output you started with

    > because the temperature reduction and area

    > increase offset each other.



    If you start with cooler water and get 73% capacity, to get back up to 100% means 1/.73 or 1.37, so the surface area needs to be 37% larger, not 27% larger.
  • JimGPE_3
    JimGPE_3 Member Posts: 240
    Watch the math...

    I agree with your basic premise (UAdT), but if you start with cooler water and get 73% capacity, to get back up to 100% means 1/.73 or 1.37, so the surface area needs to be 37% larger, not 27% larger.
  • Doug_7
    Doug_7 Member Posts: 249


    I agree with a 37% increase in area. 27% was a whoops.
This discussion has been closed.