Convector question: am I doing the math on this correctly

PeteA

Additional prep work on my part in case I do need to replace any of the convectors that I mentioned I'll be investigating on my other post. I assume the AWT is Average Water Temperature. So if I am reading the chart right OCS is saying that using a 1000 BTU multiple that I would take the 2.9 for the 24 inch x 6 inch element for a total of 2900 BTU output for the copper element and for the steel in the same size its 3.4 time the 1000 BTU's for a total of 3400 BTU's is the output that much for such a small emitter?? That seems better than many radiators which makes me wonder what these are not much more popular. Am i interpreting this correctly?
Steel element

copper element

EBEBRATT-Ed

24" long x 6" deep element installed in a cabinet 24" high =35,000 btu with awt of 180 first chart I am assuming copper

24" long x 6" deep element installed in a cabinet 24" high=38,000 btu under the same conditions.


Charts are not marked but I am assuming copper for #1 and steel for #2

PeteA

@EBEBRATT-Ed sorry about that the top chart is the steel and the bottom chart is the copper. So I am somewhat reading it correctly. Looks like your math is multiplying the 3.5 and the 3.8 by 10000 instead of 1000 though.

PeteA

labeled the charts, sorry for the oversite.

EBEBRATT-Ed

@PeteA your right I added a 0