Sizing an unusual radiator

RonBeck

Can anyone help with the Sq. Ft. Of steam for this? 2 ft Hugh x 7 ft long 2 rows of tubes.
thanks

SteamFTW

How precise do you need to get? You can get an estimate by calculating the surface area. Take a piece of string, loop it around one of the tubes, and measure the circumference. Multiply that by the length of one tube, and then multiply by 14.

Steamhead

@RonBeck , good to hear from you!

I thought that might have been made by Pressed Metal Radiator Co, but it doesn't appear in any literature that I have. @SteamFTW 's method should work.

EdTheHeaterMan

After you do the area of the pipe as @SteamFTW suggested, you then do the area of the end boxes by Multiplying the hight by the width. (yellow x green). You can also do the depth of the end box by the same method (red x green) + (red x yellow) + (red x green) + (red x yellow). Finally to get the tube connection side I would guess that there is about 20% of the connection side is open to transfer heat, so maybe (green x yellow) x 0.20. and add up all those square inches. Once you have that total number of square inches, divide it by 144" and you will have the square feet of EDR.


Here is an example:
The string around the pipe = 7.24 inches
The pipe length is 7 ft = 84 inches
7.24 x 84 = 608 square inches
608 sq in. x 14 pipes = 8,514 square inches

The box is 24"x 8" = 192 sq in.
The sides of the box is 2.5" x 24" + 2.5" x 8" + 2.5" x 24" + 2.5" x 8" = 16 sq in.
The connection side of the box is about 20% of the other side 192 sq in x 0.2 = 38 sq in.

there are 2 of those boxes @ 246 sq in.

Total sq inch of EDR = 8514 + 246 + 246 = 9000 sq inch EDR divide by 144 = 62.5 sq ft EDR

But that is just a guess on all those dimensions. You need to do the measuring and the math.

OR you can just dip that radiator in a tub of paint... Read this: where @dopey27177 recalls a story @DanHolohan would tell in his steam seminars.
https://forum.heatinghelp.com/discussion/comment/1594375#Comment_1594375
Dan always had good stories !