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Heat Load Calculation
I am doing a heat load on a new house and would like to know how to do a room with 2 1/2 walls to the outside and 1 1/2 adjacent to a garage and storage room that could see 30 degree temps (Fahrenheit). The inside temp is 70 degrees - outside is 0 degrees. How do I split the calculation?
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Basics
Basics for figuring heat loss thru an outside panel
TI-TO divided by R-Value = btu sqft
TI = Temp Indoor
TO = Temp Outdoor
Wall is 10' long 8' ceilings with no windows or doors.
(70-0)/19 = 3.68 btu x 80 = 294.4 btuhr heat loss
( 70-30)/19 = 2.11 x 80 = 168.8 btuhr heat lossThere was an error rendering this rich post.
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